The graph below shows a conic section with key points labeled. Which equation represents this graph?
Ax²/9 + y²/16 = 1
Bx²/9 − y²/16 = 1
Cy²/9 − x²/16 = 1
Dx²/16 − y²/9 = 1
Explanation
The graph shows a hyperbola opening left-right (branches on the x-axis, not top-bottom), which rules out the ellipse and the vertical-opening hyperbola. The vertices are at (±3, 0), meaning a=3 so a²=9 is under the x² term. The asymptote passes through (0,4) at a rise of 4 over the run to a=3, giving slope 4/3 = b/a, so b=4 and b²=16 is under the y² term: x²/9 − y²/16 = 1.
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