Chemistry · Semester B TEKS 14A-14C
HardCalcWord
Uranium-238 decays through a long series of alpha and beta emissions before finally reaching a stable isotope of lead. If the overall series involves 8 total alpha decays and 6 total beta-minus decays, determine the final stable isotope's mass number and atomic number, tracking both types of decay together.
AMass number 206, atomic number 82 (lead) — from 8×(−4) mass number change and (8×−2 + 6×+1) atomic number change
BMass number 206, atomic number 76 (osmium), forgetting that the 6 beta decays also affect the final atomic number
CMass number 206, atomic number 70, applying the beta decays' atomic number change in the wrong (decreasing) direction
DMass number 238, atomic number 82, forgetting that the 8 alpha decays substantially reduce mass number as well
Explanation
Each alpha decay reduces mass number by 4 and atomic number by 2; each beta-minus decay leaves mass number unchanged but increases atomic number by 1. Starting from U-238 (mass number 238, atomic number 92): mass number change = 8 alpha decays × (−4) + 6 beta decays × (0) = −32, giving a final mass number of 238 − 32 = 206. Atomic number change = 8 alpha decays × (−2) + 6 beta decays × (+1) = −16 + 6 = −10, giving a final atomic number of 92 − 10 = 82, which the periodic table identifies as lead — consistent with the stated fact that the series ends at a stable lead isotope (this specific series historically terminates at Pb-206). Forgetting that beta decay affects atomic number at all, and computing the final atomic number using only the alpha decays' contribution (92 − 16 = 76, osmium) misses beta decay's role in the series entirely. Applying beta decay's atomic number change in the wrong direction (subtracting instead of adding: 92 − 16 − 6 = 70) reverses beta-minus decay's actual proton-increasing effect. Forgetting to change mass number at all for the alpha decays (leaving it at 238) ignores alpha decay's substantial −4 mass number effect per decay event.
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