A ball is launched horizontally from the top of a 45-m-tall building with an initial speed of 12 m/s. How long does the ball take to reach the ground? Use g = 9.8 m/s² and ignore air resistance.
A3.0 s
B3.75 s
C4.59 s
D9.18 s
Explanation
📌 Vertical motion independent of horizontal. d = ½gt² → 45 = ½ × 9.8 × t² → t² = 9.18 → t ≈ 3.0 s. Distractor B divided by horizontal speed (mixed axes); C, D show incomplete calculation (stopped mid-formula or forgot square root).