A block is pushed with 50 N of force over a distance of 10 m at a 60° angle above horizontal. How much work is done? Note: cos 60° = 0.50.
Explanation
📌 W = F × d × cos θ = 50 × 10 × 0.5 = 250 J. Distractor B ignored the angle (only horizontal); C used sin instead of cos (50 × 10 × 0.866 = 433) — the sin/cos swap for work; D wrongly claims perpendicular force does zero work.