A circuit has a 12 V battery, a 2 Ω resistor, and a 4 Ω resistor in series. What is the voltage drop across the 4 Ω resistor?
Explanation
📌 Total R = 6 Ω. Current: I = 12/6 = 2 A. V across 4 Ω: V = IR = 2 × 4 = 8 V. Distractor A: value of R; B: half of source; D: full source voltage.