A ball is thrown vertically upward with an initial speed of 19.6 m/s. What is the maximum height reached? Use g = 9.8 m/s² and ignore air resistance.
A9.8 m
B19.6 m
C39.2 m
D2.0 m
Explanation
📌 Use v² = v₀² − 2gh. At max height v = 0. So 0 = 19.6² − 2(9.8)h → h = 384.16/19.6 = 19.6 m. Distractor A used v₀/2; C used 2 × correct (forgot to divide by 2); D used v₀/g, which gives time to peak (2 seconds) reported as meters — mixed units.