An electric field of 200 N/C points to the right. What is the force on a −0.05 C charge placed in this field?
A10 N right
B10 N left
C−10 N right
D4,000 N right
Explanation
📌 F = qE = (−0.05)(200) = −10 N. Negative sign means force points opposite to E: 10 N to the LEFT. Distractor A: forgot the sign; C: same as B but with awkward notation; D: multiplied wrong (0.05 × 200 = 10, not 4000).