Two 6 Ω resistors in parallel are connected in series with a 3 Ω resistor. A 12 V battery drives the circuit. What is the current from the battery?
Explanation
📌 Parallel R_p: 1/6 + 1/6 = 1/3, so R_p = 3 Ω. Total: 3 + 3 = 6 Ω. I = V/R = 12/6 = 2.0 A. Distractor B: ignored series; C: added all as series; D: added mismatched.