An electron (q = −1.6 × 10⁻¹⁹ C) enters a uniform electric field of magnitude 500 N/C. What is the magnitude of the force on the electron?
A8.0 × 10⁻¹⁷ N
B3.13 × 10²¹ N
C3.2 × 10⁻¹⁶ N
D500 N
Explanation
📌 F = |q|E = (1.6 × 10⁻¹⁹)(500) = 8.0 × 10⁻¹⁷ N. Distractor B: divided; C: extra factor of 4; D: reported E as F.