An electron moving at 2 × 10⁶ m/s enters a 0.5 T magnetic field perpendicular to its velocity. What is the magnitude of the magnetic force? Use q = 1.6 × 10⁻¹⁹ C.
A1.6 × 10⁻¹³ N
B3.2 × 10¹³ N
C2 × 10⁶ N
D0.5 N
Explanation
📌 F = qvB sin θ = (1.6×10⁻¹⁹)(2×10⁶)(0.5) = 1.6 × 10⁻¹³ N. Distractor B: wrong exponent sign; C: velocity as force; D: only B value.