Kepler's third law states T² ∝ r³. If Planet A has an orbital radius 4 times that of Planet B (around the same star), how many times longer is Planet A's orbital period?
Explanation
📌 T² ∝ r³, so T ∝ r^(3/2). If r_A = 4r_B, then T_A/T_B = 4^(3/2) = 8. Distractor A: took √r ratio; B: linear; D: squared instead of 3/2 power.