What is the force between two point charges of +3 μC and +5 μC that are 0.15 m apart? Use k = 8.99 × 10⁹ N·m²/C².
Explanation
📌 F = kq₁q₂/d² = (8.99×10⁹)(3×10⁻⁶)(5×10⁻⁶)/(0.15)² = (8.99×10⁹)(15×10⁻¹²)/0.0225 = 0.135/0.0225 = 6.0 N. Distractor A: forgot to square d; C: forgot to convert μC to C; D: forgot to divide by d².