How much heat is required to raise the temperature of 200 g of water from 20 °C to 80 °C? The specific heat of water is c = 4.18 J/(g·°C).
A12,540 J
B33,440 J
C50,160 J
D66,880 J
Explanation
📌 Q = mcΔT. ΔT = 80 − 20 = 60 °C. Q = 200 × 4.18 × 60 = 50,160 J. Distractor A used one temperature (not ΔT); B used ΔT = 40 (subtraction error); D used final temperature 80 as ΔT — the classic "used T_f instead of ΔT" mistake.