A 3.0-kg object experiences forces of 15 N north and 20 N south. What is the object's acceleration?
A5.0 m/s² north
B1.67 m/s² south
C11.67 m/s² south
D35 m/s² south
Explanation
📌 Net force = 20 south − 15 north = 5 N south. Acceleration = 5/3.0 = 1.67 m/s² south. Distractor A used wrong direction; C added forces then divided; D used sum without dividing.